perimeter = 2*width + 2*length 36= 2*8 +2*length2*length=36-162*length=20length = 10 cm
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
The length of the rectangle is 27 meters and the width is 19 meters.
Let x = width of the box. We know that the length = 3x, and that the perimeter is 2*length + 2*width, thus we have the equation 2*(3x) + 2*x = 64 => 6x+2x = 64 Combining like terms: => 8x = 64 Solving for x by dividing both sides by 8: x=8 Thus we know that the width is 8, and length = 3*x =3*8 = 24 Area = width*length = 8*24 = 192
The dimensions work out as length 15 units and width 8 units Check: 2*(15+8) = 46 units which is its perimeter
The perimeter is 38.
Perimeter = 11+11+8+8 = 38 inches
8 length 8 width
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
The width is 8 feet
Length = 16 feetWidth = 8 feetDistance around the perimeter =Length + width + length + width = 16 + 8 + 16 + 8 = 48 feet.
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
8 is length. 4 is width
2 sides have length 10 and the other 2 sides have width 8 perimeter is sum of sides = 10+10+8+8 = 36
The perimeter decreases by 4. Decreasing the length by 4 decreases the perimeter by 8. Increasing the width by 2 increases the perimeter by 4. -8+4=-4 For example: Area of a rectangle could be: 8 x 6 (8 being the length and 6 being the width). The perimeter is 8+8+6+6=28 If the length is decreased by 4 then it becomes 4 If the width is increased by 2 then it becomes 8. The perimeter becomes 4+4+8+8=24
perimeter = 2*width + 2*length 36= 2*8 +2*length2*length=36-162*length=20length = 10 cm