That depends at what value of "n" you start. For example:* Set n = 1. Calculate 5n + 1 for that value.
* Repeat for n = 2, 3, 4, and 5.
But you could also start at n = 0, for example.
29
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
9 - 5n + 1 = 15 -5n = 15 - 10 n = -5/5 n = -1
Could be anything! We'd have to know the final sum to figure out what "N" would be, like 5N +N = 24.
3n + 2n = 7 + 4n 5n = 7 + 4n 5n - 4n = 7 n = 7
7
29
first combine like terms and 5n+7=-41 add -7 to both sides 5n=-48 n=-48/5
It is 1 + 5N.
The expression ( (n + 7)5n ) can be simplified by distributing ( 5n ) to both terms inside the parentheses. This results in ( 5n \cdot n + 5n \cdot 7 ), which simplifies to ( 5n^2 + 35n ). Therefore, the answer is ( 5n^2 + 35n ).
80
5m-5n+5m+5n When simplified: 10m
it is 8.
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
31
4n + 1 = 12 + 5n First, let's get all n terms on one side and all non-n terms on the other side. Start off by subtracting 4n from each side. 1 = 12 + n Now subtract 12 from each side. -11 = n
6n + 5n is 11n.