85 - 5n or 80 - 5(n - 1)
In its lowest terms: 17/85 = 1/5
17/85 = 1/5
17/20
Let's call the smaller number n and the larger (n+9). Making the second statement into an equation: 5n = 3(n+9) + 7 5n = 3n + 27 + 7 5n = 3n + 34 2n = 34 n = 17 and n+9 = 26 Check: Do the number fit the problem? 5 * 17 = 7 + 3 * 26 85 = 7 + 78 TRUE, the numbers 17 and 26 are a valid solution for the problem.
85 - 5n or 80 - 5(n - 1)
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
The n'th term i found by subtracting n from 85 five times. n'th term = 85 - 5*nA.5 0.45n-1B.0.45 5n+1C.5 0.45nD.0.45 5nE.0.45 5n-1
85 over 102 in lowest terms = 5/6
100,90,85, 90,80,75,80.90. Rearrange the terms in rank order. 75,80,80,85,90,90,90,100. MEAN : Add all the terms together and divide by the number of terms. Hence:- (75+80+80+85+90+90+90,+100)/8 => 690/8 = 86.25 MEDIAN : Is the Absolute middle term. Since there are an even number of terms, we take the two middle terms, which are 85 & 90. (NB This leaves three terms to the left of '85' and three terms to the right of '90'. ). Add these two terms and divide by '2'. Hence (85+90) / 2 = 87.5 MODE : Is the most frequent term. The one term that appears most often. In this case it is '90', as there are three lots of '90', but only two lots of 80, and only one each of the remaining terms. = 90. .
85/100 = 17/20
51/85 + 15/85 = 66/85
85% = 85/100 = 17/20
In its lowest terms: 17/85 = 1/5
17/85 = 1/5
85/100, or in lower terms, 17/20.
55/85 = 11/17