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Sn = -8n + 2

S0 = -8(0) + 2 = 2

S1 = -8(1) + 2 = -6

S2 = -8(2) + 2 = -14

S3 = -8(3) + 2 = -22

S4 = -8(4) + 2 = -30

S5 = -8(5) + 2 = -38

Q: What are the first five terms of the sequence whose nth term is -8n plus 2?

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37

9, 17, 25, 33, 41

29

The fibbonacci sequence is 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, etc. Look at the first number. One. Look at the second number, one. Add them together and you get two which is the third number in the sequence. Now look at the one that is before the two and add that one with the two. You get three. Add the two and the three. five. Add the three and the five, 8. And so on. I hope this was helpful. The fibbonacci sequence is 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, etc. Look at the first number. One. Look at the second number, one. Add them together and you get two which is the third number in the sequence. Now look at the one that is before the two and add that one with the two. You get three. Add the two and the three. five. Add the three and the five, 8. And so on. I hope this was helpful. basicly add the last 2 numbers to get the next eg. 34+55=89

No, if it is of degree 4, it can have 4 linear factors, regardless of the number of terms.For example, x squared + 5x + 6 = (x+3)(x+2). The unfactored polynomial has three terms, and is of degree 2. Similarly, you can multiply four linear terms together; and you will get a polynomial of degree 4, which has up to 5 terms.

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