37
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
To find the first three terms, plug 1, 2, and 3 in for n:Term 1: 2(1) - 1 = 1Term 2: 2(2) - 1 = 3Term 3: 2(3) - 1 = 5
First look for the difference between the terms, for example the sequence: 5, 8, 11, 14... has a difference of 3. This means the sequence follows the 3 times table - i.e. 3n Now since we need the first term to be 5 we add 2 to our rule to make it work. So the nth term of this sequence is 3n + 2.
The first three terms for the expression 2n-6 are obtained by substituting n with consecutive integers. When n=1, the expression evaluates to -4; when n=2, the expression evaluates to -2; and when n=3, the expression evaluates to 0. Therefore, the first three terms are -4, -2, and 0.
Which sequence? Oh, that one! The first three terms are 1, 2 and 72.
10
because you add the first 2 terms and the next tern was the the sum of the first 2 terms.
123456
6
2
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
3925
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
1, 1 and 2
Ignoring the "9" , then this is a Fibonacci sequence. 2,2,4,6,10 The first two terms are 'seed' terms then successive terms equal the sum of the two previous terms. 2 + 2 = 4 2 + 4 = 6 4 + 6 = 10 The next term would be 6 + 10 = 16.
a, ar, ar^2 and ar^3 where a and r are constants.