37
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
Oh, what a lovely sequence we have here! To find the first 5 terms, we simply substitute n with 1, 2, 3, 4, and 5 into the formula 30-2n. So, the first 5 terms are 28, 26, 24, 22, and 20. Just like painting a beautiful landscape, each term in this sequence has its own unique beauty.
First look for the difference between the terms, for example the sequence: 5, 8, 11, 14... has a difference of 3. This means the sequence follows the 3 times table - i.e. 3n Now since we need the first term to be 5 we add 2 to our rule to make it work. So the nth term of this sequence is 3n + 2.
The first three terms for the expression 2n-1 can be found by substituting n with the first three consecutive integers. When n=1, the expression becomes 2(1)-1 = 1. When n=2, the expression becomes 2(2)-1 = 3. When n=3, the expression becomes 2(3)-1 = 5. Therefore, the first three terms are 1, 3, and 5.
Which sequence? Oh, that one! The first three terms are 1, 2 and 72.
because you add the first 2 terms and the next tern was the the sum of the first 2 terms.
123456
6
2
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
10
3925
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
1, 1 and 2
To find the first three terms of the sequence defined by the formula 100-3n, you simply substitute n = 1, 2, and 3 into the formula. For n = 1, the first term is 100-3(1) = 100-3 = 97. For n = 2, the second term is 100-3(2) = 100-6 = 94. For n = 3, the third term is 100-3(3) = 100-9 = 91. Therefore, the first three terms of the sequence are 97, 94, and 91.
Ignoring the "9" , then this is a Fibonacci sequence. 2,2,4,6,10 The first two terms are 'seed' terms then successive terms equal the sum of the two previous terms. 2 + 2 = 4 2 + 4 = 6 4 + 6 = 10 The next term would be 6 + 10 = 16.