-2,-4,-6.
37
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
Well, darling, the first 5 terms in that fancy sequence are 28, 26, 24, 22, and 20. You get those numbers by plugging in n values 1 through 5 into the formula 30-2n. So, there you have it, sweet cheeks!
First look for the difference between the terms, for example the sequence: 5, 8, 11, 14... has a difference of 3. This means the sequence follows the 3 times table - i.e. 3n Now since we need the first term to be 5 we add 2 to our rule to make it work. So the nth term of this sequence is 3n + 2.
The first three terms for the expression 2n-1 can be found by substituting n with the first three consecutive integers. When n=1, the expression becomes 2(1)-1 = 1. When n=2, the expression becomes 2(2)-1 = 3. When n=3, the expression becomes 2(3)-1 = 5. Therefore, the first three terms are 1, 3, and 5.
Which sequence? Oh, that one! The first three terms are 1, 2 and 72.
The sequence defined by the formula ( n^2 + 3n ) can be calculated by substituting the first three positive integers for ( n ). For ( n = 1 ), the term is ( 1^2 + 3(1) = 4 ); for ( n = 2 ), it is ( 2^2 + 3(2) = 10 ); and for ( n = 3 ), it is ( 3^2 + 3(3) = 18 ). Therefore, the first three terms of the sequence are 4, 10, and 18.
Given that the second differences of the sequence are a constant 2, the sequence can be modeled as a quadratic function. The general form of a quadratic sequence is ( an^2 + bn + c ). With the fourth term being 27 and the fifth term being 39, we can set up equations to find the coefficients. Solving these, we find that the first three terms of the sequence are 15, 21, and 27.
The nth term of the sequence given by the formula (2 - n) can be found by substituting (n) with the first three positive integers: For (n = 1): (2 - 1 = 1) For (n = 2): (2 - 2 = 0) For (n = 3): (2 - 3 = -1) Thus, the first three terms of the sequence are 1, 0, and -1.
because you add the first 2 terms and the next tern was the the sum of the first 2 terms.
123456
6
2
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
3925
10
The sequence is a geometric progression where each term is multiplied by -2 to get the next term. Starting with -4, the next terms can be calculated as follows: -4 × -2 = 8, -8 × -2 = 16, and -16 × -2 = 32. Therefore, the next three terms are 64, 128, and 256.