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well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
Assuming the recursive definition is tn = 2*tn-1 t1 = 3 t2 = 2*t1 = 2*3 = 6 t3 = 2*t2 = 2*6 = 12 t4 = 2*t3 = 2*12 = 24
This question is posed on ProjectEuler, it is for you to figure out the answer.