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If a equals 4 and d equals -2 what is the first four terms of the arithmetic sequence?
6
What are the first four terms of the sequence an 4n -1?
5
How do you find the first four terms of k equals 3n?
well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
What are the first four terms of the geometric sequence with a t1 equals 3 and tn equals 2tn-1?
Assuming the recursive definition is tn = 2*tn-1 t1 = 3 t2 = 2*t1 = 2*3 = 6 t3 = 2*t2 = 2*6 = 12 t4 = 2*t3 = 2*12 = 24
Find the sum of all the even-valued terms in the Fibonacci sequence which do not exceed four million?
This question is posed on ProjectEuler, it is for you to figure out the answer.
If a equals 4 and d equals -2 what is the first four terms of the arithmetic sequence?
6
What are the first four terms of a sequence when the nth term equals 3 to the power of n and what term number is 729 in the sequence?
The first four terms are 3 9 27 81 and 729 is the 6th term.
What are the first four terms of a sequence when the nth term equals n to the power of 4 and what term number is 14641 in the sequence?
1, 16, 81, 256 14641 is the 11th term.
What are the first four terms of the sequence an 4n -1?
5
What are the first four terms of the sequence n plus 8?
9, 10, 11 and 12
First four terms of a geometric sequence?
a, ar, ar^2 and ar^3 where a and r are constants.
What is first four terms of the arithmetic sequence with common difference of 3 and a first term of -26?
29
What is the first four terms of the sequence term 2x position number?
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
How do you find the first four terms of k equals 3n?
well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
What is the 2009Th term in the arithmetic sequence whose first four terms are twentynine sixteen and twentythree?
We need help with answering this question.
What is the first four terms of the sequence ann(2n-8)?
To find the first four terms of the sequence defined by ( a_n = 2n - 8 ), we can substitute ( n = 1, 2, 3, ) and ( 4 ). For ( n = 1 ): ( a_1 = 2(1) - 8 = 2 - 8 = -6 ) For ( n = 2 ): ( a_2 = 2(2) - 8 = 4 - 8 = -4 ) For ( n = 3 ): ( a_3 = 2(3) - 8 = 6 - 8 = -2 ) For ( n = 4 ): ( a_4 = 2(4) - 8 = 8 - 8 = 0 ) Thus, the first four terms of the sequence are (-6, -4, -2, 0).
What are the first four terms of the geometric sequence with a t1 equals 3 and tn equals 2tn-1?
Assuming the recursive definition is tn = 2*tn-1 t1 = 3 t2 = 2*t1 = 2*3 = 6 t3 = 2*t2 = 2*6 = 12 t4 = 2*t3 = 2*12 = 24
