I think it's M.
B is the second letter, C is the third, D is the 4th. The difference between these letters is one. D-G is 3 and G-J is 3 so I'd assume that the next letter is the third after J which is M.
2-3-4-7-10-13
b
g.
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
Since you are using in the arrengement the all 4 letters, then there are 4! = 4*3*2*1 = 24 permutations.
Answer 9!/3!2!=30240 Note there are three a's and two p's and a total of 9 letters in apparatus. So there are 9 choices for the first letter, and 8 for the next, then 7 for the third etc. The we divide by 3! and 2! to avoid overcounting. The answer is 9!/3!2! The numerator can be written as 9! which is pronounced 9 factorial. Then we divide that by 3! times 2! In general if you have have n letters, there are n! words you can make, However, if some of the letters are repeated you must divide to avoid overcounting. If letter a is repeated r1 times, b r2 times, c r3 times.. etc, Then the number of words is n!/r1!r2!r3!
c
B (Black). Order of snooker balls.
The sequence pattern appears to be alternating between a number and its corresponding letter in the alphabet. The numbers 1, 2, 3, 4 correspond to the letters A, B, C, D. Therefore, the next letter in the sequence would be E.
dadas
The next two letters are likely C & U. There are at least 2 patterns in these letters. FIrst is the list of vowels that make up every other letter. Then the letters alternate from the ends of the alphabet. If there is a Z, a B, then a Y, then C would likely be next, and then X. But there would be whatever vowel in sequence next.
The sequence A, Z, E, B, I, Y, O follows a specific pattern where the letters alternate between moving forward and backward in the alphabet. The first letter (A) moves to the last letter (Z), then E moves to B, and I moves to Y. Continuing this pattern, after O, the next letter should be T, as it follows the established sequence of alternating between letters in a forward and backward manner. Thus, the next letter in the sequence is T.
bb
The sequence appears to follow an alternating pattern of uppercase and lowercase letters, with the uppercase letters being A, B, D, G and the lowercase letters being h, k, j. The next uppercase letter after G could be inferred to be I, as it follows the pattern of skipping one letter (C, E, F). Therefore, the next letter in the sequence should be I.
The sequence alternates between letters in reverse alphabetical order and letters in alphabetical order. The pattern starts with 'y', followed by 'b', then 'x', 'c', and 'w'. Following this pattern, the next letter after 'w' (which is the next letter in reverse order) would be 'd'. Thus, the next letter in the sequence is 'd'.
The sequence alternates between letters from the end of the alphabet and the beginning: 'y' (2nd last), 'b' (2nd), 'x' (3rd last), 'c' (3rd), 'w' (4th last). Following this pattern, the next letter should be 'd' (4th), as it continues the alternation. Thus, the next letter in the sequence is 'd'.
bb
18 b/c the pattern is +1,+2,+3...