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How many different nine letter arrangements can be formed from the nine letters of the word apparatus?
Answer 9!/3!2!=30240 Note there are three a's and two p's and a total of 9 letters in apparatus. So there are 9 choices for the first letter, and 8 for the next, then 7 for the third etc. The we divide by 3! and 2! to avoid overcounting. The answer is 9!/3!2! The numerator can be written as 9! which is pronounced 9 factorial. Then we divide that by 3! times 2! In general if you have have n letters, there are n! words you can make, However, if some of the letters are repeated you must divide to avoid overcounting. If letter a is repeated r1 times, b r2 times, c r3 times.. etc, Then the number of words is n!/r1!r2!r3!
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How many different arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once?
That's eight letters, so: 8! = 40320 different arrangements. n! means "factorial", and the expression expands to n*(n - 1)*(n - 2) ... * 2 * 1
How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
Which two upper case letters are formed with only two perpendicular line segments?
The letters T and L are formed as asked.l and t from fiona1234
Which 2 capital letters are formed with only 2 perpendicular line segments?
X and T because the they can still make the T shape and still be perpendicular
How many subsets are there in a set formed from the letters of the word mathematics?
In a set, as it is usually defined, elements can't be repeated. "Mathematics" has 8 distinct letters, so your set would have 8 letters. The number of possible subsets (this includes the empty set, and the set itself) is two to the power 8.
