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How many different nine letter arrangements can be formed from the nine letters of the word apparatus?
Answer 9!/3!2!=30240 Note there are three a's and two p's and a total of 9 letters in apparatus. So there are 9 choices for the first letter, and 8 for the next, then 7 for the third etc. The we divide by 3! and 2! to avoid overcounting. The answer is 9!/3!2! The numerator can be written as 9! which is pronounced 9 factorial. Then we divide that by 3! times 2! In general if you have have n letters, there are n! words you can make, However, if some of the letters are repeated you must divide to avoid overcounting. If letter a is repeated r1 times, b r2 times, c r3 times.. etc, Then the number of words is n!/r1!r2!r3!
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How many different arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once?
That's eight letters, so: 8! = 40320 different arrangements. n! means "factorial", and the expression expands to n*(n - 1)*(n - 2) ... * 2 * 1
How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
Which two upper case letters are formed with only two perpendicular line segments?
The letters T and L are formed as asked.l and t from fiona1234
Which 2 capital letters are formed with only 2 perpendicular line segments?
X and T because the they can still make the T shape and still be perpendicular
How many subsets are there in a set formed from the letters of the word mathematics?
In a set, as it is usually defined, elements can't be repeated. "Mathematics" has 8 distinct letters, so your set would have 8 letters. The number of possible subsets (this includes the empty set, and the set itself) is two to the power 8.
How many different arrangements of letters in the word BOUGHT can be formed if the vowels must be kept next to each other?
240
How many different nine letter arrangements can be formed from the nine letters of the word logarithm?
Algorithm is the only nine letter word.
How many different 5 letter arrangements can be formed from the letters in the name CATHY if each letter is used only once in each arrangement?
120
How many different arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once?
That's eight letters, so: 8! = 40320 different arrangements. n! means "factorial", and the expression expands to n*(n - 1)*(n - 2) ... * 2 * 1
How many different 5 letter arrangements can be formed from the letters in the word Danny?
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
How many distinct arrangements can be formed from all the letters of student In statics?
To find the number of distinct arrangements of the letters in "student," we first note that the word contains 7 letters, with the letter 't' appearing twice. The formula for distinct arrangements of letters is given by ( \frac{n!}{p_1! \times p_2! \times \ldots \times p_k!} ), where ( n ) is the total number of letters and ( p_i ) are the frequencies of the repeated letters. For "student," this results in: [ \frac{7!}{2!} = \frac{5040}{2} = 2520. ] Thus, there are 2,520 distinct arrangements of the letters in "student."
How many different arrangements of 5 letters can be formed if the first letter must be W or K and 8203 (repeats of letters are and 8203 allowed)?
If the first letter must be either W or K, there are 2 choices for the first letter. For the remaining 4 letters, since repeats are allowed, each can be any of the 26 letters in the alphabet. Therefore, the total number of arrangements is (2 \times 26^4), which equals (2 \times 456976 = 913952).
How many different 6 letter arrangements can be formed using the letters absent if each letter is used only once?
720 (6 x 5 x 4 x 3 x 2)
How many different 7 letter arrangements can be formed from the letters in the word success?
There are 7!/(3!*2!) = 420 ways.7! for the seven letters in "success", butthere are 3 s which are indistinguishable, so divide by 3!there are 2 c which are indistinguishable, so divide by 2!
How many different 4-letter words can be formed using the letters of the word NATION?
8 different 4-letter words can be formed from the letters of the word "Nation".
How many 4 letter words can you get using aaggre?
To find the number of distinct 4-letter words that can be formed from the letters in "aaggre," we first note the available letters: a, a, g, g, r, e. The distinct combinations of letters can vary depending on how many times each letter is used. For instance, if we select two 'a's, we can combine them with different arrangements of 'g's, 'r', and 'e' to form words. The total number of distinct 4-letter combinations can be calculated by considering the different cases based on the repetitions of letters, leading to a total of 30 unique arrangements.
How many different words can be formed using letters gazebo?
Words that can be made with the letters in 'gazebo' are:aageagobagbebegboabogegogabgazegogob
