If: y = kx -2 is a tangent to the curve (which is not a circle) of y = x^2 -8x +7
Then: kx -2 = x^2 -8x +7
Transposing and collecting like terms: (8x+kx) -x^2 -9 = 0
Using the discriminant: (8+k)^2 -4*-1*-9 = 0
Multiplying out the brackets and collecting like terms: 16k +k^2 +28 = 0
Factorizing the above: (k+2)(k+14) = 0 meaning k = -2 or k = -14
Therefore the possible values of k are -2 or -14
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
To find the possible values of ( k ) for which the line ( y = kx - 2 ) is tangent to the curve ( y = x^2 - 8x + 7 ), we need to set the two equations equal and solve for ( x ): ( kx - 2 = x^2 - 8x + 7 ). Rearranging gives us the quadratic equation ( x^2 - (k + 8)x + 9 = 0 ). For the line to be tangent to the curve, this quadratic must have exactly one solution, which occurs when the discriminant is zero: ((k + 8)^2 - 4 \cdot 1 \cdot 9 = 0). Solving this gives ( k + 8 = \pm 6 ), leading to possible values ( k = -2 ) and ( k = -14 ).
product
When you graph a tangent function, the asymptotes represent x values 90 and 270.
To determine the measure of angle ( e ) in the given diagram where ( de ) and ( ef ) are tangent to circle ( o ), we can use the property that the angles formed between a tangent and a radius at the point of tangency are right angles. Therefore, if ( de ) and ( ef ) are both tangents to the circle, then the measure of angle ( e ) would typically be ( 90^\circ ). However, without specific angle values or additional information about the diagram, the exact measure cannot be determined.
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
Sine and cosine cannot be greater than 1 because they are the Y and X values of a point on the unit circle. Tangent, on the other hand, is sine over cosine, so its domain is (-infinity,+infinity), with an asymptote occurring every odd pi/2.
product
When you graph a tangent function, the asymptotes represent x values 90 and 270.
Using the discriminant the possible values of k are -9 or 9
Since there are no lists following, the answer must be "none of them!"
tangent tables are used to find values of all angles..precisely..like tan 15 degress and 25 minutes.
x (x+5) = 6 X equals 1.
A line tangent to a curve, at a point, is the closest linear approximation to how the curve is "behaving" near that point. The tangent line is used to estimate values of the curve, near that point.
1.25
SOHCAHTOAA way of remembering how to compute the sine, cosine, and tangent of an angle.SOH stands for Sine equals Opposite over Hypotenuse.CAH stands for Cosine equals Adjacent over Hypotenuse.TOA stands for Tangent equals Opposite over Adjacent. Example: Find the values of sin θ,cos θ, and tan θ in the right triangle 3, 4, 5. Answer:sin θ = 3/5 = 0.6cosθ = 4/5 = 0.8tanθ = 3/4 = 0.75
The gradient to the curve y = x2 - 8x + 7 is dy/dx = 2x - 8The gradient of the tangent to the curve is, therefore, 2x - 8.The gradient of the given line is kTherefore k = 2x - 8. That is, k can have ANY value whatsoever.Another Answer:-If: y = kx-2 and y = x2-8x+7Then: x2-8x+7 = kx-2 => x2-8x-kx+9 = 0Use the discriminant of: b2-4ac = 0So: (-8-k)2-4*1*9 = 0Which is: (-8-k)(-8-k)-36 = 0 => k2+16k+28 = 0Using the quadratic equation formula: k = -2 or k = -14 which are the possible values of k for the straight line to be tangent with the curve