If: y = kx -2 is a tangent to the curve (which is not a circle) of y = x^2 -8x +7
Then: kx -2 = x^2 -8x +7
Transposing and collecting like terms: (8x+kx) -x^2 -9 = 0
Using the discriminant: (8+k)^2 -4*-1*-9 = 0
Multiplying out the brackets and collecting like terms: 16k +k^2 +28 = 0
Factorizing the above: (k+2)(k+14) = 0 meaning k = -2 or k = -14
Therefore the possible values of k are -2 or -14
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
product
When you graph a tangent function, the asymptotes represent x values 90 and 270.
Since there are no lists following, the answer must be "none of them!"
tangent tables are used to find values of all angles..precisely..like tan 15 degress and 25 minutes.
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
Sine and cosine cannot be greater than 1 because they are the Y and X values of a point on the unit circle. Tangent, on the other hand, is sine over cosine, so its domain is (-infinity,+infinity), with an asymptote occurring every odd pi/2.
product
When you graph a tangent function, the asymptotes represent x values 90 and 270.
Using the discriminant the possible values of k are -9 or 9
Since there are no lists following, the answer must be "none of them!"
tangent tables are used to find values of all angles..precisely..like tan 15 degress and 25 minutes.
x (x+5) = 6 X equals 1.
A line tangent to a curve, at a point, is the closest linear approximation to how the curve is "behaving" near that point. The tangent line is used to estimate values of the curve, near that point.
1.25
SOHCAHTOAA way of remembering how to compute the sine, cosine, and tangent of an angle.SOH stands for Sine equals Opposite over Hypotenuse.CAH stands for Cosine equals Adjacent over Hypotenuse.TOA stands for Tangent equals Opposite over Adjacent. Example: Find the values of sin θ,cos θ, and tan θ in the right triangle 3, 4, 5. Answer:sin θ = 3/5 = 0.6cosθ = 4/5 = 0.8tanθ = 3/4 = 0.75
The gradient to the curve y = x2 - 8x + 7 is dy/dx = 2x - 8The gradient of the tangent to the curve is, therefore, 2x - 8.The gradient of the given line is kTherefore k = 2x - 8. That is, k can have ANY value whatsoever.Another Answer:-If: y = kx-2 and y = x2-8x+7Then: x2-8x+7 = kx-2 => x2-8x-kx+9 = 0Use the discriminant of: b2-4ac = 0So: (-8-k)2-4*1*9 = 0Which is: (-8-k)(-8-k)-36 = 0 => k2+16k+28 = 0Using the quadratic equation formula: k = -2 or k = -14 which are the possible values of k for the straight line to be tangent with the curve