They intersect at points (-2/3, 19/9) and (3/2, 5)
Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
They intersect at the point of: (-3/2, 11/4)
89
pythagoras
b= 10
b = 14324.80366
They intersect at the point of: (-3/2, 11/4)
The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100 Subtracting x² +100 from both sides you get 20x = -20x that will only be true when x = 0. At x = 0, y = 100 for both equations - so the point of contact would be (0,100)
104
There is no connection between the given curves because when they are combined into a single quadratic equation the discriminant of the equation is less than zero which means they share no valid roots.
89
pythagoras
b = 14324.80366
b= 10
X = √63
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
16
No, equations with the same slope do not intersect unless they are the same line.