None. If you rearrange each equation into slope intercept form ( y = mx + b), see below, you'll find that both equations have the same slope. Therefore they are parallel which also means would not intersect. Since the lines wouldn't intersect there is no solution to the system of equations.
x + 3y = 2
3y = -x + 2
y = (-1/3)x + 2/3
2x + 6y = -3
6y = -2x - 3
y = (-1/3)x - (1/2)
It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
It works out that the solutions are: x = 3 and y = 2
There is no solution for those equations because the lines are parallel so, they never touch.
The solutions are: x = -2 and y = 4
The equations are identical in value, ie the second is merely twice the first...
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
None. When these two equations are graphed, the two lines are parallel. Since they never intersect, there is no point that satisfies both equations.
Only one: (3,-2)
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
There are two solutions and they are: x = -1 and y = 3
2x - y = 8 x + y = 1 These are your two equations. They will have two solutions since you have two variables. The solutions are x=3 and y=-2
They are parallel.
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
It works out that the solutions are: x = 3 and y = 2
There is no solution for those equations because the lines are parallel so, they never touch.