Q: What are the solutions to the simultaneous equations of 2x plus y equals 5 and x squared -y squared equals 3?

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Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5

Pythagoras.

0 squared is 0. Zero times zero equals zero.

500mm=50cm and 502cm = 2500cm.

Related questions

The solutions are: x = 4, y = 2 and x = -4, y = -2

They are: (3, 1) and (-11/5, -8/5)

The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.

These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.

1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)

Through a process of elimination and substitution the solutions are s = 8 and x = 5

They are simultaneous equations and their solutions are x = 41 and y = -58

Simultaneous suggests at least two equations.

Merge the equations together and form a quadratic equation in terms of x:- 3x2-20x+28 = 0 (3x-14)(x-2) = 0 x = 14/3 or x = 2 So when x = 14/3 then y = -13/3 and when x = 2 then y = 1

Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5

Simultaneous equations.

The system is simultaneous linear equations