x = -½
2x2= 4
16
2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)
The derivative of 2x2 + 4x + 8 is 4x+4.
f(x) = 2x2 + 4x - 7
2*2+4x-9=0 4x=9-4 4x=5 x=5/4
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
x = -½
4x+4y=16 y=5 4x+ 20=16 4x=-4 x=-1
-4x-4 equals -16. Add 4 to both sides; -4x equals -12. Divide both sides by -4; x equals 3.
4x = 16Divide each side of the equation by 4:x = 4
8x + 9.16 = 4x + 16 8x - 4x = 16 - 9.16 4x = 6.84 x= 1.71
2x2= 4
It has two equal solutions of 2
4x - 8 = 16 Add 8: 4x = 24 Divide by 4: x = 6
4x - 9 = 7 4x = 16 x = 4