They are: -39 -41 -43 = -123
123/3 = 41 so integers are 39, 41 and 43
123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.
x is lowest of the integers so x + (x + 2) + (x + 4) = 123 ie 3x + 6 = 123 so 3x = 117 and x = 39, so integers are 39, 41 and 43
The numbers are 121, 122 and 123.
They are 40, 41 and 42.
Find three consecutive positive even integers whose sum is 123 , Answer
The numbers are 39, 41 and 43.
They are: -39 -41 -43 = -123
123/3 = 41 so integers are 39, 41 and 43
123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.
There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.
x is lowest of the integers so x + (x + 2) + (x + 4) = 123 ie 3x + 6 = 123 so 3x = 117 and x = 39, so integers are 39, 41 and 43
between which two consecutive integers does the square root lie 123
39,41,43! Ya
The numbers are 121, 122 and 123.
61 & 62