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What are the values of k when the line kx plus y equals 4 touches the curve y equals x squared plus 8 on the Cartesian plane showing work?
Wiki User
∙ 7y ago
If: y = x^2 +8 and kx +y = 4 or y = 4 -kx
Then: x^2 +8 = 4 -kx
So: x^2 +8 -4 +kx = 0 => x^2 +4 +kx = 0
Using the discriminant b^2 -4ac = 0: k^2 -4*1*4 = 0 => k^2 = 16
Therefore the values of k are: -4 or 4
Hence: y-4x = 4 and y+4x = 4 are tangents to the curve y = x^2 +8
Wiki User
∙ 7y ago
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