If: y = x^2 +8 and kx +y = 4 or y = 4 -kx
Then: x^2 +8 = 4 -kx
So: x^2 +8 -4 +kx = 0 => x^2 +4 +kx = 0
Using the discriminant b^2 -4ac = 0: k^2 -4*1*4 = 0 => k^2 = 16
Therefore the values of k are: -4 or 4
Hence: y-4x = 4 and y+4x = 4 are tangents to the curve y = x^2 +8
66 squared equals 4,356.
xx^(2) + y^(2) = 25 => x^(2) + y^(2) = 5^(2) This is the circle equation, in Cartesian Co-ordinates. It is also the Pythagorean Eq'n.
X = √63
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
one squared equals one.
It is the Cartesian equation of an ellipse.
Points of intersection work out as: (3, 4) and (-1, -2)
Equation of circle: x^2 +y^2 -8x -y +5 = 0Completing the squares: (x-4)^2 +(y-0.5)^2 = 11.25Centre of circle: (4, 0.5)Slope of radius: -1/2Slope of tangent: 2Equation of tangent: y-2 = 2(x-1) => y = 2xNote that the above proves the tangent of a circle is always at right angles to its radius
Improved Answer:-If: 2x+y = 5 and x^2 -y^2 = 3Then by rearranging: y = 5 -2x and -3x^2 -28+20x = 0Solving the above quadratic equation: x = 2 and x = 14/3By substitution points of intersection are: (2, 1) and (14/3, -13/3)
The two solutions are (x, y) = (-0.5, -sqrt(3.5)) and (-0.5, sqrt(3.5))
The number that equals 121 when squared is 11.
5.477225575 squared equals 30.
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
b = sqrt32 or 4 root 2
No, it equals -2xy. lrn2math
4
This is a point on the cartesian coordinate plane... (10,13)