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y = 2x2 - 3x - 20
∴ y = 2x2 - 8x + 5x - 20
∴ y = 2x(x - 4) + 5(x - 4)
∴ y = (2x + 5)(x - 4)
The x intercepts occur when y = 0, which happens when either of the two factors on the left side of the equation equal zero. This means that they are at the points (-5/2, 0) and (4, 0).
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What are the x-intercepts of y 2x2 - 3x - 20?
They are at: x = -2.5 and x = 4
What is the roots of the equation 2xsquare-3x-4 equals 0?
2x2 -3x - 4 = 0 use the qudratic equation and your answers are 1.137458609 and -2.637458609
X2 plus 7x equals -2x2 plus 6?
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
The system of equations 3x-6y equals 20 and 2x-4y equals 3 is?
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.
What is 3x times 4y equals?
12xy
What are the roots of the quadratic equation y equals 2x2 plus 3x-20?
2x2 + 3x - 20 = (x + 4)(2x - 5).
2x2 - 3x plus 7?
2x2 equals 5
Is y equals 3x plus 1 and -2x2 a function?
No.
How do you complete the square 2x2 - 3x plus 1 equals 0?
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
What is 2x2 equals 3x?
2X2 = 3Xset to 02X2 - 3X = 0factorX(2X - 3) = 0zero factor rule2X = 3 = 02X = 3X = 3/2======X = 0X = 3/2
What is the solution set 2x2-3x-1 equals 0?
(-2,-1)
Value of the discriminant for 2x2 - 3x plus 1 equals 0?
The discriminant is 1.
2x2 equals 3x equals 3x-12-x2?
3x=3x-12-x**20=-12-x**2x**2=-12 (not possible w/ real numbers)x=i(12)**0.5=2i(3)**0.52x**2=3x2(-12)!=3(2i(3)**0.5)Equations do not equateEquation is wrong
What are the x-intercepts of y 2x2 - 3x - 20?
They are at: x = -2.5 and x = 4
What is the roots of the equation 2xsquare-3x-4 equals 0?
2x2 -3x - 4 = 0 use the qudratic equation and your answers are 1.137458609 and -2.637458609
2x2-3x plus 1 equals 0?
(2x - 1)(x - 1) so x = ½ or 1
What is the answer to 2x2-3x-1 equals 0?
No solution in integers, Quadratic formula gives roots as 1.78 and -0.28
