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What are the x-intercepts of y equals 2x2 - 3x - 20?
y = 2x2 - 3x - 20 ∴ y = 2x2 - 8x + 5x - 20 ∴ y = 2x(x - 4) + 5(x - 4) ∴ y = (2x + 5)(x - 4) The x intercepts occur when y = 0, which happens when either of the two factors on the left side of the equation equal zero. This means that they are at the points (-5/2, 0) and (4, 0).
How many points does the graph of the function below intersect the x-axis y 2x2 - 3x plus 1?
y = 2x2 - 3x + 1 y = (x - 1)(2x - 1) x - 1 = 0 2x - 1 = 0 x = 1 x = 1/2 the answer is 2
Find the equation of the tangent at x3 to the curve y2x squared - 3x 2?
The tangent to the curve y = 2x2 - 3x + 2 at x=3 first we differentiate the eqution and get dy/dx = 4x -3 feed in the x=3 dy/dx = 9 So we now know that the gradient of the tangent is 9 We can also find out one of the points that is passes through. y = 2x2 - 3x + 2 when x = 3 y = 2*32 - 3*3 + 2 y = 29 So we have a line of gradient 9 that passes through the pint (3,29) We can now find out the y intercept 29 - (3*9) = 2 y = 3x + 2
What is the y-intercept of the graph 3x - 4y equals 20?
-5
What is the vertex of y-2x2-4x-5?
2x2= 4
