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Here are two ways to solve this:

Intuitively:

three consecutive even integers with a sum of 42 must be centered around 42/3=14. The answer is 12, 14, and 16, which can be verified by adding them: 12+14+16=42

Or algebraically:

With N the lowest even integer:

N+N+2+N+4=42

3N=36

N=12

So the answer is 12, 14, and 16.

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Q: What are three consecutive even integers with a sum of 42?
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