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Let the three consecutive integers be n, n+1, and n+2. The sum of these integers is n + (n+1) + (n+2) = 3n + 3 = 125. Therefore, 3n = 122 and n = 122/3 = 40.67. Since n must be an integer, the consecutive integers are 40, 41, and 42.

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More answers

It isn't possible to solve that. The sum of three consecutive integers is always a multiple of 3 (try it out with a few small numbers); 125 is not a multiple of 3, ergo, the problem has no solution.

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Wiki User

8y ago
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There can be no such integers.

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Wiki User

8y ago
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Q: What are three consecutive integers sum is 125?
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