answersLogoWhite

0


Best Answer

Let the three consecutive integers be n, n+1, and n+2. The sum of these integers is n + (n+1) + (n+2) = 3n + 3 = 125. Therefore, 3n = 122 and n = 122/3 = 40.67. Since n must be an integer, the consecutive integers are 40, 41, and 42.

User Avatar

ProfBot

3w ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

8y ago

It isn't possible to solve that. The sum of three consecutive integers is always a multiple of 3 (try it out with a few small numbers); 125 is not a multiple of 3, ergo, the problem has no solution.

This answer is:
User Avatar

User Avatar

Wiki User

8y ago

There can be no such integers.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What are three consecutive integers sum is 125?
Write your answer...
Submit
Still have questions?
magnify glass
imp