What are three consecutive integers sum is 125?

Answer 1

Let the three consecutive integers be n, n+1, and n+2. The sum of these integers is n + (n+1) + (n+2) = 3n + 3 = 125. Therefore, 3n = 122 and n = 122/3 = 40.67. Since n must be an integer, the consecutive integers are 40, 41, and 42.

Answer 2

It isn't possible to solve that. The sum of three consecutive integers is always a multiple of 3 (try it out with a few small numbers); 125 is not a multiple of 3, ergo, the problem has no solution.

Answer 3

There can be no such integers.