They are: 5 and 14
We will get two values of y . One is y=6 and another is y=13
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
19 & 17
Oh, dude, you're hitting me with some math here! Okay, so the sum of 19 and the product of 34 is... drumroll, please... 685! It's like adding 19 to the result of multiplying 34 by 1, which gives you 685. Math, man, it's wild.
The sum of two numbers witha difference of two equals forty can be set up and solved this way: x + (x - 2) = 40 2x - 2 = 40 2x = 42 x = 21 x - 2 = 19 The two numbers are 21 and 19.
If two numbers have a sum of 31 and a product of 228, then the two numbers are 12 and 19. Adding them will give you 31, and multiplying them gives you 228.
6 and 13
16 and 3
The two numbers are 19 and 7. 19 + 7 = 26, and 19 x 7 = 133.
67
441
19
1.61013 and 17.38987 (approx).
The two numbers are 6 and 13 so therefore the smaller number is 6
13 + 6 = 19 19 + 6 = 25. 19 X 6 = 114.
To solve this problem, we are looking for two numbers that multiply to 150 and add to -19. Let’s break it down: Product of the two numbers: The two numbers should multiply to give 150. Sum of the two numbers: The same two numbers should add up to -19.
If you meant "what two prime numbers have a sum of 36?" the answer is 19 and 17.