19
None, if the coefficients of the quadratic are in their lowest form.
To find two numbers whose sum is 16 and product is 63, we can set up the equations ( x + y = 16 ) and ( xy = 63 ). By substituting ( y = 16 - x ) into the product equation, we get ( x(16 - x) = 63 ), which simplifies to ( x^2 - 16x + 63 = 0 ). Solving this quadratic equation, we find the numbers are 7 and 9, as ( 7 + 9 = 16 ) and ( 7 \times 9 = 63 ).
If you mean: (x-2)(x+4) = 0 then it is a quadratic equation whose solutions are x = 2 or x = -4
When the equation is a polynomial whose highest order (power) is 2. Eg. y= x2 + 2x + 10. Then you can use quadratic formula to solve if factoring is not possible.
Numbers whose product is one is called multiplicative inverses.
The numbers are 15.75 and -5.75 When tackling probiems like this form a quadratic equation with the information given and solving the equation will give the solutions.
The quadratic formula can be used to find the solutions of a quadratic equation - not a linear or cubic, or non-polynomial equation. The quadratic formula will always provide the solutions to a quadratic equation - whether the solutions are rational, real or complex numbers.
that's impossibleAnswer:xy=9 and x+y=12reduces to the quadratic equation x2-12x+9=0so that once solvedx=-11.196 and y=-0.80385 (approx)
2
None, if the coefficients of the quadratic are in their lowest form.
To find two numbers whose sum is 16 and product is 63, we can set up the equations ( x + y = 16 ) and ( xy = 63 ). By substituting ( y = 16 - x ) into the product equation, we get ( x(16 - x) = 63 ), which simplifies to ( x^2 - 16x + 63 = 0 ). Solving this quadratic equation, we find the numbers are 7 and 9, as ( 7 + 9 = 16 ) and ( 7 \times 9 = 63 ).
2
If you mean: (x-2)(x+4) = 0 then it is a quadratic equation whose solutions are x = 2 or x = -4
When the equation is a polynomial whose highest order (power) is 2. Eg. y= x2 + 2x + 10. Then you can use quadratic formula to solve if factoring is not possible.
Numbers whose product is one is called multiplicative inverses.
To find the numbers that maximize the product p, we can use the formula for a quadratic equation: x = -b / 2a. Let's call one number x and the other number (120-x). Therefore, the equation becomes x(120 - x^2), which simplifies to -x^3 + 120x. We can find x by setting the derivative equal to zero, resulting in x = 10. Therefore, the two numbers that maximize the product are 10 and 110, with a product of 12100.
3 and 7 are prime numbers whose product is 21.