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Find the value of k for which the equation 2x2 - parenthesis k - 1 parenthesis x plus 80 equals 0 will have real and equal roots?
A quadratic of the form ax² + bx + c = 0 has two equal (real) roots when the determinant of b²-4ac = 0. Thus, for: 2x² - (k - 1)x + 80 = 0 b² - 4ac = (-(k - 1))² - 4×2×80 = 0 → (k - 1)² = 640 → k - 1 = ±√640 → k = 1 ± √640 → k ≈ 26.298 or -24.298
What does 0 degrees k mean?
The "k" is Kelvin, a temperature scale like Fahrenheit or Celsius. "0" Kelvin is absolute zero. For more on Kelvin see: http:/en.wikipedia.org/wiki/Kelvin For more about absolute zero, see: http:/en.wikipedia.org/wiki/Absolute_zero
Solving quadratic equations by factoring?
(k + 1)(k - 5)= 0
How would you write the algebraic expression double k then subtract 5?
If you mean: kk-5 then it can be k^2-5 But if you mean: k+k-5 then it can be 2k-5
What s the value of k when the equation x squared plus 2kx plus 10x plus k squared plus 5 equals 0 has equal roots?
Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Multiplying out the brackets: 4k^2 +40K +100 -4k^2 -20 = 0 Collecting like terms: 40k +80 = 0 => 40k = -80 => k = -80/40 Therefore the value of k = -2
