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A quadratic of the form ax² + bx + c = 0 has two equal (real) roots when the determinant of b²-4ac = 0. Thus, for:

2x² - (k - 1)x + 80 = 0

b² - 4ac = (-(k - 1))² - 4×2×80 = 0

→ (k - 1)² = 640

→ k - 1 = ±√640

→ k = 1 ± √640

→ k ≈ 26.298 or -24.298

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Q: Find the value of k for which the equation 2x2 - parenthesis k - 1 parenthesis x plus 80 equals 0 will have real and equal roots?
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