The direction of the inequality remains unchanged. The direction changes when you divide or multiply both sides by a negative number. It also changes if both sides are raised to a negative exponent.
When you divide both sides by a negative value
You solve an inequality the same way you solve an equality. You add and subtract, multiply and divide, both sides by the same value in order to isolate one of the variables. The only extra thing you need to remember is that if you multiply or divide by a negative number, you must reverse the order of the inequality, i.e. less than or equal becomes greater than or equal.
Divide both sides by 9: 9x > 27 → x > 3
a solution of inequality
When the value indicated by the circle is a valid value for the inequality.
Inequality signs stay the same when you add or subtract the same value from both sides of an inequality because this operation does not change the relative sizes of the quantities. For example, if ( a < b ) and you add ( c ) to both sides, it remains ( a + c < b + c ). However, if you multiply or divide both sides by a negative number, the inequality sign must be flipped to maintain the correct relationship.
When you divide both sides by a negative value
You solve an inequality the same way you solve an equality. You add and subtract, multiply and divide, both sides by the same value in order to isolate one of the variables. The only extra thing you need to remember is that if you multiply or divide by a negative number, you must reverse the order of the inequality, i.e. less than or equal becomes greater than or equal.
No. Only when you divide by a negative.
To solve the inequality (-2x + 8 < 5x + 2x + 1), first combine like terms on the right side: (5x + 2x = 7x). The inequality simplifies to (-2x + 8 < 7x + 1). Next, add (2x) to both sides, resulting in (8 < 9x + 1). Subtract (1) from both sides to get (7 < 9x), and then divide by (9) to find (x > \frac{7}{9}). Thus, any value greater than (\frac{7}{9}) satisfies the inequality.
When a quantity is subtracted or added from both sides of an inequality, the true difference in value is varied thereby changing the direction of the inequality, but when rather than subtracted or added it is multiplied or divided, it preserves the true difference in value thereby facing the same direction as the initial inequality.
(X+6)/4 >= 2 First, remove the fraction on the left side by multiplying both sides by four X+6 >= 8 Subtract 6 from both sides to get your X value X >= 2
6 + 2x = x - 6 Subtract x from both sides: 6 + x = -6 Subtract 6 from both sides: x = -12
You need to solve for a by getting it by itself. You do this by performing the same operation on both sides of the equation 3a + 2 = a -6 subtract 2 from both sides: 3a = a -8 subtract a from both sides: 2a = -8 divide both sides by 2: a = -4
Divide both sides by 9: 9x > 27 → x > 3
Can you provide me with an inequality problem that the value is the same?
It is an equation used to anwer an absolute value inequality.