You need to solve for a by getting it by itself. You do this by performing the same operation on both sides of the equation
3a + 2 = a -6
subtract 2 from both sides:
3a = a -8
subtract a from both sides:
2a = -8
divide both sides by 2:
a = -4
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2 + 3A + 9A = 2 + 12AThe numerical value depends on the value of 'A'.It changes whenever 'A' changes.
a + 3a - 2 + 3a. Add the a + 3a + 3a = 7a. You can't combine the -2 & 7a so the solution is: 7a - 2.
x^3 + ax + 3a + 3x^2 = (x^3 + 3x^2) + (ax + 3a) = x^2(x + 3) + a(x + 3) = (x + 3)(x^2 + a)
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
The answer to the expression 3a + 4 depends on the value of 'a' as it is a variable. If 'a' is a specific number, you would first multiply 3 by 'a' and then add 4 to the result. For example, if 'a' is 2, the answer would be 3(2) + 4 = 6 + 4 = 10. In general, the expression simplifies to 3a + 4.