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What if the first term of a trinomial has no coefficients the middle term takes the sign of what?
Wiki User
∙ 8y ago
Nothing: it can have either sign.
Wiki User
∙ 7y ago
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How many seconds it takes within the first puff of a cigarette to travel to your brain?
Well if you want to be precise it takes 0.341783 seconds if you have done in the past and. But if its your first time it takes 0.715069
It takes you 60 seconds to walk from the first ground floor of a building to the fourth floor. How long will it take to walk from the first floor to the eighth floor?
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When a trinomial is factored as (x a)(x b) what is the sum of a and b?
Thanks to the rubbish browser which you are required to use for posting questions, we cannot see most mathematical symbols. It is, therefore, not possible to give an unambiguous answer.The algebraic sum of a and b is the coefficient of the middle term - the term for x.Incidentally, the algebraic sum is the sum of a and b which takes account of their signs.
Why liquids have two coefficients of expensions?
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How do you factor 12x2 plus 28x-17?
The trick with this kind of question is to find two terms that add up to the middle one (28x), and whose coefficients are equal multiples of the first and last term: 12x2 + 28x - 17 = 12x2 - 6x + 34x - 17 = 6x(2x - 1) + 17(2x - 1) = (6x + 17)(2x - 1) The only trick with this technique is that sometimes it's difficult to find those two middle terms (-6x and 34x in this case). If it takes too long to figure this out, you can actually break it down into ~another~ quadratic equation, which will usually be easier to factor, and give you those two values. Consider: Let "a" and "b" be the unknown coefficients. We know: b = 28 - a <-- we know this because they must add up to the middle term 12/a = b/17 <-- this must be true in order for us to end up with a common multiple. ∴ 12/a = (28 - a)/17 ∴ 28a - a2 = 204 ∴ a2 - 28a + 204 = 0 We can then solve for "a" by factoring this equation: (a - 34)(a + 6) = 0 So our coefficients are the two possible values for "a", 34 and -6. We can then simply plug them in to the original equation and factor it out as shown above.
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