a^(2)- 2ab - 15b^(2)
When the first term has a coefficient of '1' (a^(2)), then look at the third term.
It is '15'. So we need two numbers that multiply to '15' and 'add/subtract'to '2'.
They are 3. & 5.
So writing up our brackets
( a 5b)(a 3b)
Which signs???
We note from the quadraic , that '15' is negative(-) . So the brackets need one positive(+) and one negative(-)
Since the middle term is also negative(-) , then the larger numerical number takes the negative.
Hence
( a - 5b)(a + 3b)
Done!!!!
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a3-4a = a(a2-4) when factored
(a2+2b2-2ab)(a2+2b2+2ab)
2AB
(a-b)2 = a2 _ 2ab+b2
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2