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How do you Write an equation in the form of y equals kx for the following data?
There are no "following" data!
What is the value of k in the line of y equals kx plus 1 and is tangent to the curve of y squared equals 8x?
If: y = kx+1 is a tangent to the curve y^2 = 8x Then k must equal 2 for the discriminant to equal zero when the given equations are merged together to equal zero.
What are the values of k when the line kx plus y equals 4 touches the curve y equals x squared plus 8 on the Cartesian plane showing work?
If: y = x^2 +8 and kx +y = 4 or y = 4 -kx Then: x^2 +8 = 4 -kx So: x^2 +8 -4 +kx = 0 => x^2 +4 +kx = 0 Using the discriminant b^2 -4ac = 0: k^2 -4*1*4 = 0 => k^2 = 16 Therefore the values of k are: -4 or 4 Hence: y-4x = 4 and y+4x = 4 are tangents to the curve y = x^2 +8
What is the value of k when the line y equals kx plus 1.25 is a tangent to the curve y squared equals 10x?
Equations: y = kx +1.25 and y^2 = 10x If: y = kx +1.25 then y^2 = (kx +1.25)^2 =>(kx)^2 +2.5kx +1.5625 So: (kx)^2 +2.5kx +1.5625 = 10x Transposing terms: (kx)^2 +2.5kx +1.5625 -10x = 0 Using the discriminant formula: (2.5k -10)^2 -4(1.5625*k^2) Multiplying out the brackets: 6.25k^2 -50k +100 -6.25^2 = 0 Collecting like terms: -50k +100 = 0 Solving the above equation: k = 2 Therefore the value of k is: 2
What are the values of k when the line of y equals kx -2 is a tangent to the curve of y equals x squared -8x plus 7?
If: y = kx -2 and y = x^2 -8x+7 Then the values of k work out as -2 and -14 Note that the line makes contact with the curve in a positive direction or a negative direction depending on what value is used for k.
