answersLogoWhite

0

What if y equals kx?

User Avatar

Anonymous

14y ago
Updated: 4/28/2022

You then have a linear relationship, or a direct variation. A straight line through the origin.

User Avatar

Wiki User

14y ago

Still curious? Ask our experts.

Chat with our AI personalities

EzraEzra
Faith is not about having all the answers, but learning to ask the right questions.
Chat with Ezra
BlakeBlake
As your older brother, I've been where you are—maybe not exactly, but close enough.
Chat with Blake
BeauBeau
You're doing better than you think!
Chat with Beau

Add your answer:

Earn +20 pts
Q: What if y equals kx?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Algebra

How do you Write an equation in the form of y equals kx for the following data?

There are no "following" data!


What is the value of k in the line of y equals kx plus 1 and is tangent to the curve of y squared equals 8x?

If: y = kx+1 is a tangent to the curve y^2 = 8x Then k must equal 2 for the discriminant to equal zero when the given equations are merged together to equal zero.


What are the values of k when the line kx plus y equals 4 touches the curve y equals x squared plus 8 on the Cartesian plane showing work?

If: y = x^2 +8 and kx +y = 4 or y = 4 -kx Then: x^2 +8 = 4 -kx So: x^2 +8 -4 +kx = 0 => x^2 +4 +kx = 0 Using the discriminant b^2 -4ac = 0: k^2 -4*1*4 = 0 => k^2 = 16 Therefore the values of k are: -4 or 4 Hence: y-4x = 4 and y+4x = 4 are tangents to the curve y = x^2 +8


What is the value of k when the line y equals kx plus 1.25 is a tangent to the curve y squared equals 10x?

Equations: y = kx +1.25 and y^2 = 10x If: y = kx +1.25 then y^2 = (kx +1.25)^2 =>(kx)^2 +2.5kx +1.5625 So: (kx)^2 +2.5kx +1.5625 = 10x Transposing terms: (kx)^2 +2.5kx +1.5625 -10x = 0 Using the discriminant formula: (2.5k -10)^2 -4(1.5625*k^2) Multiplying out the brackets: 6.25k^2 -50k +100 -6.25^2 = 0 Collecting like terms: -50k +100 = 0 Solving the above equation: k = 2 Therefore the value of k is: 2


What are the values of k when the line of y equals kx -2 is a tangent to the curve of y equals x squared -8x plus 7?

If: y = kx -2 and y = x^2 -8x+7 Then the values of k work out as -2 and -14 Note that the line makes contact with the curve in a positive direction or a negative direction depending on what value is used for k.