Add the vectors by components. That is, add the "i" components, and separately add the "j" components.
3j + j = 4j
The complex conjugate of 2-3i is 2+3i.
The conjugate of 2 + 3i is 2 - 3i, and the conjugate of 2 - 5i is 2 + 5i.
To form the additive inverse, negate all parts of the complex number → 8 + 3i → -8 - 3i The sum of a number and its additive inverse is 0: (8 + 3i) + (-8 - 3i) = (8 + -8) + (3 + -3)i = (8 - 8) + (3 - 3)i = 0 + 0i = 0.
2 + 5j
3i+2j)*(2i-3j)=0 bcz dot product is zero.
Assuming you mean:F1 = 3i - 4j + 2k,F2 = 2i + 3j - k,F3 = 2i + 4j - 5k.Simply add all of them algebraically, i.e. add i's to i's, j's to j's etc. - this works in all dimensions.The resultant force F will be in your case:F = 7i + 3j - 4k.
To find the magnitude of the resultant displacement (\mathbf{R} = \mathbf{A} + \mathbf{B}), we first add the vectors: [ \mathbf{R} = (5i - 23) + (-3i + 4j + 6k) = (5 - 3)i + 4j + 6k - 23 = 2i + 4j + 6k - 23. ] This simplifies to (\mathbf{R} = 2i + 4j - 17). The magnitude of (\mathbf{R}) is given by: [ |\mathbf{R}| = \sqrt{(2)^2 + (4)^2 + (-17)^2} = \sqrt{4 + 16 + 289} = \sqrt{309} \approx 17.578. ] Thus, the magnitude of the resultant displacement is approximately 17.58 m.
3j + j = 4j
- 2 - 3i
If vector a and b are truly identical, their resultant angle will be the same. Their resultant velocity will not be the same, however. Assuming you mean the magnitudes are the same, the two vectors will be at an angle of 120o
36.64
0 + 3i
11
if b + a , since a+b equals b + a due to it being commutative . it shud have the same magnitude and direction
The complex conjugate of 2-3i is 2+3i.
Without information about j, the only possible answer is 3j + 15