2 + 5j
Add the vectors by components. That is, add the "i" components, and separately add the "j" components.
It is (3j)^6.
c + j = 42; c + 5 = 3(j + 5) c = 42 - j so 42 - j + 5 = 3j + 15 ie 47 - j = 3j + 15 ie 4j = 32 so Jared is 8 and Chim 34 and in 5 years Jared will be 13 and Chim 39. QED
15j2(j + 2)
4
Without information about j, the only possible answer is 3j + 15
3j-13=11+2j 3j-13-2j = 11+2j-2 j-13 = 11 j-13 +13 = 11 + 13 = 24 so j = 24
-3j = 44.7 -j = 44.7 ÷ 3 -j = 14.9 j = -14.9
(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)
2 + 5j
An equation where j = 3
An equation where j = 3
3i+2j)*(2i-3j)=0 bcz dot product is zero.
Add the vectors by components. That is, add the "i" components, and separately add the "j" components.
To calculate the torque, you can use the cross product formula: Torque = r x F, where r is the position vector and F is the force vector. Given r = i - j + k and F = 7i + 3j - 5k, calculate their cross product to find the torque about the origin.
It is (3j)^6.