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Find the inverse of f x 3x plus 9?
f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
F(x)=3x+9?
12
2.If fx 12x and gx 3 x find and simplify the defining equation of the composition function f circle g.?
The composite function f of g is also expressed as f(g(x)). In this case, it would be 12(3x), or 36x.
When gx and fgx are known how do you find fx where fx gx are functions of x and fgx is a function of gx?
Since g(x) is known, it helps a lot to find f(x). f(g(x)) is a new function composed by substituting x in f with g(x). For example, if g(x) = 2x + 1 and f(g(x)) = 4x2+ 4x + 1 then you you recognize that this is the square of the binomial 2x + 1, so that f(g(x)) = (f o g)(x) = h(x) = (2x + 1)2, meaning that f(x) = x2. if you have a specific example, it will be nice, because there are different ways (based on observation and intuition) to decompose a function and write it as a composite of two other functions.
If f of x equals 3x - 10 then what is f of 2a?
if f(x) = 3x - 10, then whatever is put (substituted) for x in the "f(x)" bit is substituted for x in the "3x - 10" bit. Thus f(2a) = 3(2a) - 10 = 6a - 10.
