f(x) = 1/3x3
f'(x) = ∫ 1/3x3 dx
f'(x) = 1/3∫ x3 dx
f'(x) = 1/3 * 3 * x2
f'(x) = x2
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THE DERIVATIVE OF 1/3X³ IS X² BECAUSE IF Y = 1/3X³ AND DY/DX = 31/3X² = X², YOU CAN ALSO CHECK THIS VIDEO FOR BETTER EXPLANATION
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
The derivative of y = 1/3 x3 - 3x2 + 8x + 1/3 is x2 - 6x + 8. You can determine this for yourself by the rules. The derivative of a constant (e.g. 1/3) is 0. The derivative of xn for positive n (actually all nonzero n) is nxn-1. And if the derivative of f(x) is f'(x), then the derivative of k f(x) is k f'(x). Put all these together and you get the above result.
The derivative of ln x is 1/x The derivative of 2ln x is 2(1/x) = 2/x
Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.
The derivative of 3cos(x) is -3sin(x). This can be found using the chain rule, which states that the derivative of a composition of functions is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function. In this case, the derivative of cos(x) is -sin(x), and when multiplied by the constant 3, we get -3sin(x) as the derivative of 3cos(x).