4
The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.
Take the derivative of (3x+1)1/2First use the power rule on the entire function, then multiply it by the derivative of the inside:(1/2)(3x-1)-1/2(3) = (3/2)(3x-1)-1/2which can also be written as3/(2sqrt(3x-1))(sqrt stands for square root)
If y = 3x +- 1, the derivative with respect to x is y' = 3.
f'(x)=-3the derivative of e is zero because its a constant. Derivative of -3x is -3. Bring the exponent of x down in front of the -3 and subtract the original exponent by 1. Ex. -3(1...which is the first exponent of the x)x^0(n-1 or 1-1=0)all this is -3(1)x^0x^0 is 1 so the derivative of -3x is -3
-1
To calculate the first derivative of a function, you can follow these general steps: Identify the function: Determine the function for which you want to find the first derivative. Let's assume your function is denoted as f(x). Express the function: Write down the function in its general form, considering any constants or variables involved. For example, f(x) = 3x^2 + 2x - 1. Differentiate the function: Use differentiation rules to find the derivative of the function. The derivative represents the rate of change of the function with respect to the variable. For example, to differentiate f(x) = 3x^2 + 2x - 1, apply the power rule and the sum rule as follows: Power rule: For a term of the form ax^n, the derivative is d/dx(ax^n) = anx^(n-1). Sum rule: The derivative of a sum of functions is the sum of their derivatives. Applying these rules to the function f(x) = 3x^2 + 2x - 1: The derivative of the term 3x^2 is 6x (using the power rule). The derivative of the term 2x is 2 (using the power rule, where the exponent is 1). The derivative of the constant term -1 is 0 (as the derivative of a constant is always 0). So, the first derivative of f(x) = 3x^2 + 2x - 1 is f'(x) = 6x + 2. Simplify if necessary: If there are any further simplifications or rearrangements possible, apply them to obtain the final form of the first derivative. In summary, the process involves differentiating each term of the function with respect to the variable and then simplifying the resulting expression. Differentiation rules such as the power rule, sum rule, product rule, and chain rule can be used depending on the complexity of the function.
The derivative of y = sin(3x + 5) is 3cos(3x + 5) but only if x is measured in radians.
I think you mean; f(x) = 3x^2 d/dx(3x^2) = 6x
3e3x
3sec2(3x)
11
3x - 4 sqrt(2)The first derivative with respect to 'x' is 3.