No.
The given expressions can be simplified to: 7y-8x-14
Without an inequality sign it is not an inequality equation but the given expression can be simplified to: 8x-16-7y
8x - 7y = 7 (A)7x + 8y = 8 (B)7*(A): 56x - 49y = 498*(B): 56x + 64y = 648*(B)-7*(A): (64+49)*y = 64-49=> 113y = 15=> y = 15/113
2x times 4x is 8x squared- then that times x is 8x to the power of three.Mathmatically represented as 8x^3
7y+ 8x + 4= 20 + 8x- 8x - 8x7y + 4 = 20- 4 - 47y=16/7 /7y= 2.28the /7 means divide by 7 :)
-8x -7y
The simplest way is to rewrite the equation in the standard for: y = mx + c. Then the slope is m. 8x - 7y = 56 7y = 8x - 56 y = 8/7 * x - 8 So the slope is 8/7
8 over 7.
-8x-6y=-18
Put in function form. 8X - 7Y = 168 - 7Y = - 8X + 168 Y = 8/7X - 24 0 out Y 8/7X - 24 = 0 8/7X = 24 X = 21 ---------- 0 out X Y = - 24 ----------- (21,-24) X and Y intercepts.
No.
no its not a solution
y-5x
If the equations are 8x + 7y = 37, and 2y = 4x -2 then the answer is yes.
8x - 7y + 2 = 0 The slope-intercept form is NOT the standard form. The above form is easily generalised to 3 (or more) dimensions, not so with the slope-intercept form.
(3,7)