Mathmatically represented as 8x^3
y = 2x-5 4x-y = 7 => y = 4x-7 2x-5 = 4x-7 2x-4x = 5-7 -2x = -2 x = 1 Therefore by substituting: x = 1 and y = -3
(The original question was misphrased.) 4x-7 = 2x+5 resolves as 2x-7 = 5 2x = 12 x = 6
Simplify 4x + 3 = 2x + 8 2x = 5 x =2½
A = 2x(x - 2) = 2x2 - 4x
2x/3=x/2+20 (2x/3=x/2+20)6 4x=3x+120 4x-3x=120 x=120
2x + 4x - x = 5x
If 4x - 2x + 4 = 10, the solution is 2x + 4 = 10 and x = 3.
4x+9=2x-6 2x=-15 x=-7.5 x equals -7.5.
2x = 4x + 3 -2x = 3 x = -3 / 2
-2x = -4x + 24 -2x + 4x = 24 2x = 24 x = 24/2 x = 12
5-4x=12-2x isolate your x's on one side 5=12-2x+4x 5-12=-2x+4x simplify -7=2x divide by 2 x=-7/2, or x=-3.5
-2x=-4x*24 x=12
2x + 33 = 4x + 11 -11 -11 2x + 22 = 4x -2x -2x 22 = 4x Divide each side by 4 x = 5.5
2x+4-x = 4x-5 2x-x-4x = -5-4 -3x = -9 x = 3
3x - 5x + 4x = -2x +4x = 2x
2x+17 = 4x-3 2x-4x = -3-17 -2x = -20 Answer: x =10
60-2x = 70-4x 60-2x+2x = 70-4x+2x 60 = 70 +2x 60-70 = 70 + 2x - 70 -10 = 2x x = -10/2 = -5