0/2 is 0. Imagine it like this: I have $0 to give two people - how much can I possibly give each person? Nothing because I have nothing to give.
2x^2 - 8x = -82x^2 - 8x +8 = 0, bring the -8 over to the other side2 (x^2 - 4x + 4) = 0, simplify2 (x - 2) (x - 2) = 0, factor out the equation2 = 0, x - 2 =0, x - 2 =0 , set everything egual to zero and solve for xx = 22=0 does not have an answer because it is invalid or it doesn't have a variable like the rest; 2 does not equal 0.
Integral from 0 to pi 6sin2xdx: integral of 6sin2xdx (-3)cos2x+c. (-3)cos(2 x pi) - (-3)cos(2 x 0) -3 - -3 0
To find the mean, you add all the numbers together and divide by the amount of numbers (in this case, 6). 2+4+2+0+1+2=11. 11 divided by 6 is equivalent to 11 over 6 (11/6), 1 5/6 (one and five sixths), or 1.83333333 with the 3 repeating (draw a line over the 3).
12b2 - 8b = 0 4b(3b-2) = 0 4b = 0 and 3b-2 = 0 4b = 0 and 3b = 2 b = 0 and 2/3
0/2 = 0
0 over 2 equals to 0 divided by 2. Therefore, the answer is zero.
Yes; 0/2=0
2
Zero
1 over 2
2 A++++++ Rise 4 _ Over 2 (4/2) -----> Rise 2 _ Over 1 (2/1) ------> 2 al3xisnic0le
If you mean the slope between (-7, -2) and (4, -2), the answer is 0 because the rise over the run is 0 over 11 which equals 0.
1/2
x^2/x +2=4/x +2 (x^2/x)-(4/x)=0 (x^2-4)/x=0 x^2-4=0 (x+2)(x-2)=0 x=±2
[(log1)/2](8)=(0/2)(8)=0
The answer is:cos (pi/2) = 0