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2 x cosine squared x -1 which also equals cos (2x)
That factors to (x - 2)(x + 4) x = 2, -4
x^2+2x^2=3x^2
2
(2x - 7)(x + 1)
2 x cosine squared x -1 which also equals cos (2x)
x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0
If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
(x - 3)(x + 5)
2(x - 2)(x - 4)
That factors to (x - 2)(x + 4) x = 2, -4
Yes it is and well done.
No, x + x equals 2x. x times x equals x2. (x times x equals x squared.)
1 +/- the square root of 3
x^2+x^2=2x^2
2x + 52 = 7 2x + 25 = 7 2x = 7 - 25 2x = -18 x = -18/2 x = -9
If you mean: 2x squared = 50 Divide both sides by 2: x squared = 25 Square root both sides: x = 5