Q: What is 2 times y times y divided by 4?

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Y = 4/x^2

If that's y times 4, the answer is 4y

(x+y)/2

x = 2 so x squared = 4 and 2x squared = 2 times 4 = 8; y = 4 so xy = 2 times 4 = 8 and 3xy = 3 times 8 = 24; y squared = 4 times 4 = 16 and 4y squared = 4 times 16 = 64; so 8 + 24 - 64 = 32 - 64 = -32

(y - 4)/(x-2) = (4 - (-6) )/(2 - (-3)) = 22 x - 4 = y - 4y = 2x(y - 4)/(x-2) = (4 - (-6) )/(2 - (-3)) = 22 x - 4 = y - 4y = 2x

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y = 2

18

if INVERSELY proportional then y = 1/X^2 ( that is, 1 divided by x squared) If X doubles then X SQUARED increases as 2 x 2 = 4 times SINCE Y = 1/x^2 then Y DECREASES 4 times

Y = 4/x^2

If that's y times 4, the answer is 4y

2x / (y-2) + 2x / (2-y)First get a common denominator: (y-2) (2-y)Then you have:2x(2-y) / (y-2)(2-y) + 2x(y-2) / (y-2)(2-y), summing and simplifying, you get:(4x-4) / (y-2)(2-y)

1*1*1*1*1+1=4 divided by4

X^4 divided by Y^2

0.5

It depends on where there are parentheses, if there are any. y + 33 + 2/4 = y + 27.5 (y+3)3 + 2/4 = y3 + 9y2 + 27y + 27.5

Improved Answer:If: x = -2 and y = -4Then: xy = 8Because: -2 times -4 = 8

The product of y times 4 is equal to y multiplied by 4. Similarly, the product of y times 6 is equal to y multiplied by 6.