What is X if 2x + 4 = 36 What is X ? 2x + 4 = 36
2x + 12 y =36subtract 2x from both sides12y = 36 - 2xdivide both sides by 12y = (36 - 2x)/12
If you mean: 6x+6y = 36 and 2x-2y = 20 then its works out x = 8 and y = -2
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
8x + 38 = 2x + 2 The first thing you want to do is get all the variables on one side and all the stand-alone numbers on the other side. To do this, you just do the opposite of what the sign is (Ex: Since it is "plus 38" on the left side, to get it to the right we subtract 38) 8x = 2x + 2 -38 Now you can simplify the right side: 8x = 2x -36 And then you want to get the variables on the left side of the problem. So since 2x is positive, you want to subtract 2x from both sides of the equation. 8x - 2x = -36 Simplify the left side: 6x = 36 And then from there you can divide both sides by 6. x = 6
What is X if 2x + 4 = 36 What is X ? 2x + 4 = 36
2x + 12 y =36subtract 2x from both sides12y = 36 - 2xdivide both sides by 12y = (36 - 2x)/12
what is the answer to 2x-18<36
2x + 4 = 362x = 36 - 42x = 32x = 32/2X = 16
The value of X in the equation 2x plus 36 = 4 is -16.
It can be simplified to: 2x+86
2x + 7 = 79 Subtract '7' from both sides/ Hence 2x = 72 Divide both sides by '2' Hence x = 36 .
1/2x+6=1/3x 3x+36=2x 3x=2x-36 x=-36
let the no be x then, 4x=36+ (-2x) 4x+2x =36 6x = 36 x =6
Presumably the question is about finding the dimensions of a rectangle? Let the length be 2x-3 and the width be x: 2(2x-3+x) = 36 4x-6+2x = 36 4x+2x = 36+6 6x = 42 x = 7 Therefore: length = 11 units and width = 7 units
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
It is 288x - 432.