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What is 2xy plus 6xy?
2xy + 6xy = 8xy
What are the like terms of 3xy 5-2xy 10?
3xy and 2xy. You can see that 3xy and 2xy have something in common with each other. They both have xy and the end of them. Hope this helped.
What is 5xy - x2t plus 2xy plus 3x2t?
What is : 5xy- x2t + 2xy + 3x2t
What is the answer to 3x2-27?
3x2-27 is equal to -21.
Factor 2xy - 4x plus 8y - 16?
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
How do you work this problem 3x2 2xy-y20?
3 x 2 = 2y - 20y6 = -18y-0.33333 = y
3x squared plus 6xy plus 3y squared?
3x2+6xy+3y2= 3(x2+2xy+y2)= 3(x+y)2
What is the greatest common factor of 2xy and 2x2y?
Since 2xy is a factor of 2x2y, it is automatically the GCF.
What is 2xy plus 6xy?
2xy + 6xy = 8xy
2xy + 2xy squared?
(x + 4y)(x - 6y)
3xsquare-2ysquare equals 9xsquare plus 4ysquare-12xy how do you reach this answer?
3x2 - 2y2 = 9x2 + 4y2 - 12xy (subtract 3x2 and add 2y2 to both sides) 0 = 9x2 -3x2 + 4y2 + 2y2 - 12xy 0 = 6x2 + 6y2 - 12xy (divide by 6 to both sides) 0 = x2 + y2 - 12xy or x2 - 2xy + y2 = 0 (x - y)(x - y) = 0 x - y = 0 x = y
What is the square root of 18xy in radical form?
√18xy = √(9*2xy) = √9*√2xy = 3*√(2xy)
What is the greatest common factor of 4xy and -6xy?
The greatest common factor of 4xy and -6xy is 2xy. To find the greatest common factor, we first factor out the numbers 4 and -6 to get 2(2xy) and -2(3xy). The greatest common factor is the highest common factor that divides both terms evenly, which in this case is 2xy.
What is 2xy times x?
To find the product of 2xy and x, you multiply the coefficients (2 and 1) to get 2, then multiply the variables x and x to get x^2, and finally multiply the variables y and 1 to get y. Therefore, the result of 2xy times x is 2x^2y.
What is the terms of-3xy2 plus 2xy-4y3?
The three terms are: -3xy2, 2xy and -4y3
How do you write four times the product of x and y decreased by 2xy?
4xy - 2xy
What are the like terms of 3xy 5-2xy 10?
3xy and 2xy. You can see that 3xy and 2xy have something in common with each other. They both have xy and the end of them. Hope this helped.
