Let the five consecutive intgers be , n, n+1, n+2, n+3, ^ n +4 Summing n + (n+1) + (n+2) + (n+3) + (n +4) = 170 Hence 5n + 10 = 170 5n = 160 n = 160/5 n = 32 Hence the five consecutive intgers are: 32,33,34,35, & 36
(x+4)2 - (x)(x+2) = 34 (x^2 + 8x + 16) - (x^2 + 2x) = 34 6x + 16 = 34 6x = 18 x = 3
multiplication is point to point and convolustion is point to multi-point ex multiplication-- s[n]=x[n].h[n] s[0]=[x[0].h[0] s[1]=[x[1].h[1] s[2]=[x[2].h[2] . . . .. s[n-1]=[x[n-1].h[n-1] convollustion s[n]=x[n]*h[n] s[0]=[x[0].h[0]+x[0].h[1]+x[0].h[2]+.......+x[0].h[n-1] s[1]=[x[1].h[0]+x[1].h[1]+x[1].h[2]+.......+x[1].h[n-1] s[2]=[x[2].h[2]+x[2].h[1]+x[2].h[2]+.......+x[2].h[n-1] . . . s[n-1]=[x[n-1].h[0]+x[n-1].h[1]+x[n-1].h[2]+.......+x[n-1].h[n-1].
17x + 34 factors to 17(x + 2)
2
38 + (n/2) = 21 Therefore, n/2 = -17 n = -17 x 2 n = -34
2
n/2 = 60 Therefore, n = 60 x 2 n = 120
8.5
The law of powers requires that xn divided by xm = x(n - m). Consider this when n = m: xn divided by xn = x(n - n), ie 1 = x0. x2 = x times x x1 = x times x divided by x ie x x0 = x divided by x = 1 x-1 = 1 divided by x = 1/x x-2 = 1/x divided by x ie 1/x2 etc
x/4 = 34 Multiply both sides by '4' x = 136 The answer!!!!!
17
25
The equation is #of sides x (#of sides - 3) divided by 2. Equation: N x (N-3) 2
1 x 34, 2 x 17, 17 x 2, 34 x 1
2 divided by x-12-x divided by x-2 is -1/(6(x-2)).
Rounded to two decimal places, (35 - 3723 + (34 x 2)) / 23.4 = -154.70