Circumference: 2*pi*3 = 6*pi inches Area: pi*3 squared = 9*pi square inches
The formula for the volume of a square is: A = 4/3 * pi * r3 Therefore A = 4/3 * pi * 33 = 4/3 * pi * 27 = 36 * pi = approx 113.10 m3
The circumference C is pi times the diameter of the circle, which is twice the radiusC= pi *2rThe area A is pi times the radius squaredA = pi r2where pi = about 3.14159Example:For a radius of a 3 cmC = pi x (3 x 2) = pi x 6 = about 18.85 cmA = pi x (3)2 = pi x 9 = about 28.275 cm2
Volume of sphere = 4/3*pi*r3 So volume of half a sphere = 2/3*pi*r3= 2/3*pi*103 = 2000*pi/3 = 2094.4 cubic units
V=4/3 X pi X r3Since you have the volume formula, I don't understand why you're having difficulty.volume = (4/3) * pi * r*r*rvolume = (4/3) * pi * 125volume = (500*pi)/3volume = 523.59877559833Thus, the volume of the sphere is approximately523.6 cubic centimeters.volume = (4/3) * pi * r^3 and since we know that r=5volume = (4/3) * pi * 5*5*5approximating "pi" as 3.14159265359volume = (500*3.14159265359)/3
9
[pi^(1/3)]^2 * pi = pi^(2/3) * pi = pi^(5/3) The answer is the cubic root of pi to the fifth power.
18pi m^3 ~ 56.5486678 m^3 sphere: (4/3)pi(r^3) hemisphere: ((4/3)pi(r^3))/2=(4/6)pi(r^2)=(2/3)pi(r^3) d=6 r=3 (2/3)pi(3^3)=(2/3)pi(27)=(54/3)pi=18pi
(pi + pi + pi) = 3 pi = roughly 9.4248 (rounded) Well, if you use the common shortened version of pi which is 3.14 and add that 3 times, you get 9.42.
Volume of a sphere = 4/3 pi R3V = (4/3) (pi) (2)3 = 8/3 pi = 8.3776(rounded)
No, the volume formula is not universal for all figures. Different shapes and objects have different formulas to calculate their volume based on their unique dimensions and properties. Each shape requires its own specific formula to accurately determine its volume.
Yes
11pi/12 = pi - pi/12 cos(11pi/12) = cos(pi - pi/12) cos(a-b) = cos(a)cos(b)+sin(a)sin(b) cos(pi -pi/12) = cos(pi)cos(pi/12) + sin(pi)sin(pi/12) sin(pi)=0 cos(pi)=-1 Therefore, cos(pi -pi/12) = -cos(pi/12) pi/12=pi/3 -pi/4 cos(pi/12) = cos(pi/3 - pi/4) = cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) cos(pi/3)=1/2 sin(pi/3)=sqrt(3)/2 cos(pi/4)= sqrt(2)/2 sin(pi/4) = sqrt(2)/2 cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) = (1/2)(sqrt(2)/2 ) + (sqrt(3)/2)( sqrt(2)/2) = sqrt(2)/4 + sqrt(6) /4 = [sqrt(2)+sqrt(6)] /4 Therefore, cos(pi/12) = (sqrt(2)+sqrt(6))/4 -cos(pi/12) = -(sqrt(2)+sqrt(6))/4 cos(11pi/12) = -(sqrt(2)+sqrt(6))/4
Circumference: 2*pi*3 = 6*pi inches Area: pi*3 squared = 9*pi square inches
No, for example if A = Pi/3. Then sin3A = sin pi = 0, but sinA = sin Pi/3 = 1/2. So for A = Pi/3, the sum is 1/2, not zero. It can't be proved because the statement is false. For example if A = Pi/3. Then sin3A = sin pi = 0, but sinA = sin Pi/3 = 1/2. So for A = Pi/3, the sum is 1/2, not zero.
3 + pi =3πor6.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679821480865132823066470938446095505822317253594081284811174502841027019385211055596446229489549303819644288109756659334461284756482337867831652712019091456485669234603....
Volume is not necessarily in pi. For example, the volume of a cube, with sides of 3 cm is 3*3*3 = 27 cubic cm. Not a hint of pi anywhere in that!