{-1,-2}
4x+3/3=y
You have 2 equations and 2 unknowns so you can solve 2x-3y = -11 y = 4x -3 2x - 3y = -11 -4x + y = -3 multiply 1st equation by 2 both sides: 4x-6y = -22 -4x + y = -3 add: -5y = -25 y = 5 substitute y = 5 into either equation: -4x+y = -3 -4x +5 = -3 -4x = -8 x = 2
Presumably this is a simultaneous equation in the form of: -4x+3y = 27 -2x+y = -1 Multiply all terms of the bottom equation by 2: -4x+3y = 27 -4x+2y = -2 Subtract the bottom equation from the top equation remembering that a - - is equal to a + Meaning that -4x - -4x = 0 and 27 - -2 = 29: So y will = 29 Substitute the value of y into the original equations to find the value of x Therefore: x = 15 and y = 29
4x + 3y = 1y = 2x + 8 Take the first part: 4x + 3y = 1y 4x = 1y - 3y 4x = -2y x = -y/2 Substitute x in second part: 1y = 2x + 8 1y = -2y/2 + 8 1y = -1y + 8 2y = 8 y = 4 Substitute y into either part: 1y = 2x + 8 1(4) = 2x + 8 4 - 8 = 2x -4 = 2x x = -2 Therefore: x = -2 y = 4
-1/2
There are two simultaneous equations, so to solve for y, eliminate x: 1) 2x + 3y = 3 2) 4x - 3y = 9 Multiply equation (1) by 2 giving: 1) 4x + 6y = 6 2) 4x - 3y = 9 Next, subtract equation (2) from equation (1), giving: (4x - 4x) + (6y - -3y) = 6 - 9 → 9y = -3 → y = -1/3
second equation x 2: 4x + 6y = 4 subtract first equation: 9y = 3 so y = 1/3 and x = 1/2
16x2 + 8x + 1 - 9y2 = (4x + 1)2 - (3y)2 which is a difference of two squares. = (4x + 1 + 3y)*(4x + 1 - 3y)
4x+3y = 6 3y = -4x+6 y = -4/3x+2 in slope intercept form
8x-3y=6-4x gives 12x-3y=6 which in standard form is y=-2+4x
x = 5 y = 2 4x - 3y = ? 4(5) - 3(2) = ? 20 - 6 = 14
Let's see. 2X + 3Y = 12 3Y = - 2X + 12 Y = -2/3X + 4 ---------------- 6Y - 4X = 2 6Y = 4X + 2 Y = 2/3X + 1/3 --------------------- Nope. They can't be. Plot a few points and see.
(2, 2)
You need to organise your question properly. 3x+2y=4 4x + 3y= 7? Is 4 4x = 44x or 4-4x or 4+4x How can there be 2 equal signs in 1 equation?
(5, 2)
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.