It is: 2b squared
12 squared plus 18 squared is equal to 468.
6 squared plus 9 squared is equal to 117.
Sin squared, cos squared...you removed the x in the equation.
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
[square root (78)] squared = 78. There is not a surd from for an integer.
No because 78 times 78 doesnt equal 78
78 - 72 = 29
First you square root everything on both sides to cancel the squares. 30+B=78 Then subtract 30 from both sides to get B=48. So the answer is B=48
78 minus78
Deductive reasoning, trial and error. The square root of 78 will be between 8 and 9, closer to 9. 8.7 squared = 75.7 8.8 squared = 77.4 8.9 squared = 79.2 8.8 is the closest without going over.
78
78 feet squared.
81 - 3 = 78 81 - -3 = 84
9 squared is 81. Two digits lower than 81 is 79. 79 is a prime number. Its only factors are one and itself. That does not compute. 78 has 26 and 6 as factors. 78 is three digits lower than 81. That does not compute.
92 = 81 91/2 = 3 Thus, 81 - 3 = 78.
156 = 2 * 78 = 2 * 2 * 39 = 2 * 2 * 3 * 13