It is: 2b squared
12 squared plus 18 squared is equal to 468.
6 squared plus 9 squared is equal to 117.
Sin squared, cos squared...you removed the x in the equation.
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
If you mean 84 squared then it is 84*84 = 7056 If you mean the square root of 84 then it is 2 times the square root of 21 which is an irrational number
Yes - 7056 is equal to 84 squared.
x/1 + x/x = 84 where x = a prime number that is divisible by 1 and itself. Then find common denominator of 1x. Then we have x squared/1x + x/1x = 84. To simplify this will be x squared + x/1x = 84. The this becomes 1 + x = 84. Then x = 83. The prime numbers are 1 and 83 which fit the equation.
The GCF of 84 and 144 is 12. You must do the prime factorization of each number. The prime factorization of 144 is 2 to the fourth power times 3 squared. The prime factorization of 84 is 2 squared times 7 times 3. You take the least of each common factor which would be 2 squared and 3. Two squared equals 4 and 4 times 3 equals 12, so the GCF is 12.
Assuming it's a rectangle, 6048 squared inches
There are 12in in a foot, therefore the tiles are 1 squared foot each. So you should ideally need 84 tiles
if you have a TI-84 you can hit math, then go down to the x before the square root sign
81 - 3 = 78 81 - -3 = 84
7x2+49x+84 = 0 Divide all terms by 7: x2+7x+12 = 0 Factorize: (x+3)(x+4) = 0 Therefore the x intercepts are -3 and -4
he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared
2 squared X 3 squared = 5 squared
9x squared-15x squared = -6