If you mean: 9x squared+6x+1 = 0 then x = -1/3 and x = -1/3 therefore the quadratic equation has equal roots
-1
Equation would be 9x2-1=0 Thus: 9x2=1 x2=1/9 x= square root of 1/9 Therefore: x=1/3
1
x squared +6x +5 is a quadratic expression that can be factored as (x+1)(x+5)
6(x-1) 2x3(x-1)
9x2+6x-7 = 0 Using the quadratic equation formula:- x = 0.6094757082 or x = -1.276142375
3x(x - 2)
-6x + 9x2 - 24 = 3(3x2 - 2x - 8) = 3(3x2 - 6x + 4x - 8) = 3(3x(x - 2) + 4(x - 2)) = 3(3x + 4)(x - 2)
k = -3; factors are (9x + 3)(x - 1)
2 x 2 x 3 x 2 x 2 x 7 x 2 x 2 x 2 = 27 x 3 x 7 or 2688
The discriminant of a quadratic ax2 + bx + c is b2 - 4ac; thus: the discriminant of -9x2 + 6x + 14 is 62 - 4 x -9 x 14 = 540
Yes it can be solved and X=0.
x = 5y3/6
y=6x² is already solved. the parabola will touch the x-axis at x=0.
-1
9x2 + 7x = 2 9x2 + 7x - 2 = 0 9x2 + 9x - 2x - 2 = 0 9x(x + 1) - 2(x + 1) = 0 (9x - 2)(x + 1) = 0 x ∈ {-1, 2/9}
(3x - 2)(9x2 + 6x + 4)