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Q: What is the discriminent of 9x2 plus 12x equals 2?

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9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared

x=5

Given, 3x2 - 4x = -2 Then, 9x2 - 12x = -6; 9x2 - 12x + 4 = -2 {completing the square} ; 3x - 2 = ±i√2 {sq rt of both sides} ; and 3x = 2 ± i√2. Therefore, x = ⅓(2 ± i√2).

The discriminant is 0.

9x2+6x-7 = 0 Using the quadratic equation formula:- x = 0.6094757082 or x = -1.276142375

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9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2

There's a chance this was notated incorrectly. It looks like it wants to be some combination of 3x and 2. 9x2 + 12x + 4 = (3x + 2)(3x + 2) or (3x + 2)2 -9x2 - 12x - 4 = -(3x + 2)2 9x2 - 12x + 4 = (3x - 2)2 -9x2 + 12x - 4 = -(3x - 2)2

-9x 2 -12x+5 =

9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared

x=5

Given, 3x2 - 4x = -2 Then, 9x2 - 12x = -6; 9x2 - 12x + 4 = -2 {completing the square} ; 3x - 2 = ±i√2 {sq rt of both sides} ; and 3x = 2 ± i√2. Therefore, x = ⅓(2 ± i√2).

The discriminant is 0.

9x2 - 12x + 4 = 0 is of the form ax2 + bx + c = 0 where the discriminant, D, can be found by D = b2 - 4ac First, you find the values of a, b and c: a = 9 b = -12 c = 4 Now you can find D: D = (-12)2 - (4)(9) = 144 - 36 = 108 D = 108

Presumably this is a quadratic equation question in the form of: 9x2-12x+4 = 0 When factored: (3x-2)(3x-2) = 0 Solution: x = 2/3 and also x = 2/3 (they both have equal roots)

I x=5 and y=2, then (5x5)=25 plus (9x2)=18. 25+18=43

9x2+6x-7 = 0 Using the quadratic equation formula:- x = 0.6094757082 or x = -1.276142375

It is a quadratic equation and its solutions can be found by using the quadratic equation formula.

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