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What is Length and width of a rectangular lot with a perimeter of 132 meters if the length is 8 meters more than the width?
Wiki User
∙ 12y ago
2L+2W=132
L=W+8
substitute for L...
2(W+8)+2W=132
2W+16+2W=132
4W+16=132
2W+8=66
2W=58
W=29
L=W+8=29+8=37
So the width is 29 metres and the length is 37 metres
Wiki User
∙ 12y ago
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