4x-x2 = 2
X2 + 4xx(x + 4)=======
x2 + x + 6
[ x3 - 4x2 + 7x ] / (x) = x2 - 4x + 7
It is: 4x -34x^2 -21 simplified
You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)
4x-x2 = 2
-2
(x2 + 4x + 4)/(x + 2) Is this the correct question? And what are you asking?
x+5 is a factor of x2+4x-5 use synthetic division to learn that the other factor is x-1
x2 - 4x - 32 = (x - 8)(x + 4)
No. x2 -4x - 12 = (x + 2)(x - 6)
x2 - 4x - 9 = 0 ∴ x2 - 4x = 9 ∴ x2 - 4x + 4 = 13 ∴ (x - 2)2 = 13 ∴ x - 2 = ±√13 ∴ x = 2 ± √13
x2 + 4x + 6 can not be factored. If you want, you can reduce it to an expression with a single x term by comleting the square: x2 + 4x + 6 = x2 + 4x + 4 + 2 = (x + 2)2 + 2
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
x2 - 4
(x2 - 4)/4x = 12; x ≠ 0 x2 - 4 = 48x x2 - 48x = 4 x2 - 48x + 242= 4 + 242 (x - 24)2 = 4 + 576 x - 24 = ±√580 x = 24 ± 2√145