You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
(x2+3x-4) (x-4)
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
y = 4x-3
x2 - 4x + 4 factors to (x - 2)(x - 2) or (x - 2)2
4x-x2 = 2
When factored: (x+4)(x-8)
x2 + 4x - 60 factors into (x + 10)(x - 6). You can use the FOIL method to check your answers when you factor.
x2 + 4x - 21 = (x + 7)(x - 3). The trick is to find 2 numbers which sum to 4 and have a product of -21.
(x + 1) and (x + 2) are monomial factors of the polynomial x2 + 3x + 2 (x + 1) and (x + 3) are monomial factors of the polynomial x2 + 4x + 3 (x + 1) is a common monomial factor of the polynomials x2 + 3x + 2 and x2 + 4x + 3
if that's +32, it factors to -(x - 4)(x + 8)
(x+7) and (x-3)
6
X2 - 4X - 5 as an expression, or equation is factorable when the question, what two factors of - 5 add to - 4 is answered ( X + 1)(X - 5) X = - 1 ------------and X = 5 ---------------
x2 - 4x - 32 = (x - 8)(x + 4)
No. x2 -4x - 12 = (x + 2)(x - 6)